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How to find the distinct elements in an array in Kotlin

How to find the distinct elements in an array in Kotlin.

Here's a step-by-step tutorial on how to find the distinct elements in an array using Kotlin.

Step 1: Initialize an array​

To begin, you'll need to initialize an array containing multiple elements. Here's an example of how you can create an array in Kotlin:

val array = arrayOf(1, 2, 3, 4, 1, 2, 5, 6, 3, 4, 7, 8)

In this example, we have an array named array with 12 elements.

Step 2: Create a set​

A set is a collection that contains only unique elements. In Kotlin, you can easily create a set from an array using the toSet() function. Here's how you can do it:

val distinctElements = array.toSet()

The distinctElements set will now contain only the distinct elements from the array.

Step 3: Convert the set back to an array (optional)​

If you need the result as an array instead of a set, you can convert the set back to an array using the toTypedArray() function. Here's an example:

val distinctArray = distinctElements.toTypedArray()

The distinctArray will now contain the distinct elements in the form of an array.

Step 4: Print the distinct elements​

You can now print the distinct elements to verify the result. Here's an example that uses a loop to print each element on a new line:

for (element in distinctElements) {
    println(element)
}

This will print each distinct element from the array on a new line.

Step 5: Putting it all together​

Here's the complete code that puts all the steps together:

val array = arrayOf(1, 2, 3, 4, 1, 2, 5, 6, 3, 4, 7, 8)
val distinctElements = array.toSet()
val distinctArray = distinctElements.toTypedArray()

for (element in distinctElements) {
    println(element)
}

This code will initialize an array, find the distinct elements, convert them back to an array if needed, and print the distinct elements.

That's it! You now know how to find the distinct elements in an array using Kotlin.